FRANK Solutions for Class 10 Chemistry Chapter 10 - Study of Sulphur Compound: Sulphuric Acid

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 249

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 250

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 251

Question 1

Choose the current answer from the options given below :

(i) In the preparation of H₂SO₄ by contact process V₂O₃ is used as a catalyst in the reaction. It is

(a) S + O₂→ SO₂

(b) SO₂ + H₂SO₄→ H₂S₂O₇

(c) SO₃ + H₂O → H₂SO₄

(d) 2SO₂ + O₂→ 2SO₃

(ii) When conc. H₂SO₄ comes in contact with sugar, it becomes black due to

(a) Hydrolysis

(b) Decolourisation

(c) Dehydration

(d) Hydration

(iii) Which of the following gas dissolves in H₂SO₄ to give alum?

(a) SO₂

(b) H₂S

(c) S₂O

(d) SO₃

(iv) In the contact process, the impurities of arsenic are removed by

(a) Fe₂O₃

(b) Fe(OH)₃

(c) AlCOH₃

(d) Cr(OH)₃

(v) The catalyst used for the oxidation of SO₂ to SO₃ in contact process is

(a) Finally divided iron

(b) Molybdenum

(c) Vanadium

(d) Nitric oxide

Solution 1

(i) 2SO₂ + O₂→ 2SO₃

(ii) Dehydration

(iii) SO₃

(iv) Fe(OH)₃

(v) Vanadium pentoxide

Question 2

Fill in the blank with appropriate word/words :

(i) The catalyst used in contact process for the manufacture of H₂SO₄ is platinum or Vanadium pentoxide

(ii) For the reaction SO₂ + O₂⇌ SO₃ + Heat, the favorable conditions are high pressure and low temperature

(iii) Oil of Vitriol is ___________

Solution 2

(i) The catalyst used in contact process for the manufacture of H₂SO₄ is ___________ or _________.

(ii) For the reaction SO₂ + O₂⇌ SO₃ + Heat, the favourable conditions are _________ and __________.

(iii) Oil of vitriol is sulphuric acid.

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 252

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 253

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 254

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

(a)         B
(b)         D
(c)         C
(d)        A
(e)        A

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 255

Question 1

Solution 1

Question 2

Write the equation for each of the following reactions :

(i) Sulphur is heated with concentrated sulphuric acid

(ii) Concentrated sulphuric acid is poured over sugar

Solution 2

(i) S + H₂SO₄→ 3SO₂ + 2H₂O

(ii) 

Question 3

State your observation for the following cases :

(i) Moist blue litmus is introduced into a gas jar of sulphur dioxide

(ii) Dry red rose petals are placed in the jar of sulphur dioxide

(iii) Paper soaked in potassium permanganate solution is introduced into a gas jar of sulphur diaoxide.

Solution 3

(i) Litmus turns blue to red, and then gets bleached.

(ii) Dry SO₂ has no effect on dry red rose petals.

(iii) Paper turns from pink to white.

Question 4

What would you observe in the following case :

Sugar crystals are added to hard glass test tube containing concentrated sulphuric acid.

Solution 4

Charring of sugar takes place. Sulphuric acid dehydrates sugar leaving behind carbon which is black.

Question 5

(i) With the help of equations, give an outline for the manufacture of sulphuric acid by the contact process

(ii) What property of sulphuric acid is shown by the reaction of concentrated sulphuric acid when heated with

(i) Potassium nitrate

(ii) carbon

Solution 5

(i) Formation of sulphur dioxide:

S + O₂ → SO₂

Conversion of SO₂ to SO₃

Conversion of sulphur trioxide to oleum:

SO₃ + H₂SO₄→ H₂S₂O₇

Dilution of oleum:

H₂S₂O₇ + H₂O → 2H₂SO₄

(ii)  

i. Non-volatile nature

ii. As an oxidising agent

Question 6

In the given equation identify the role played by concentrated sulphuric acid S + 2H₂SO₄→ 3SO₂ + 2H₂O

(a) Non-volatile acid

(b) Oxidising agent

(c) Dehydrating agent

(d) None of the above

Solution 6

(b) Oxidising agent

Question 7

State one appropriate observation for each of the following.

(i) Concentrated sulphuric acid is added dropwise to a crystal of hydrated copper sulphate.

(ii) Dehydration of Concentrated Sulphuric acid with sugar crystals

Solution 7

(i) When conc. H₂SO₄ is added to a crystal of hydrated copper sulphate, it removes water of crystallisation from salt.

(ii) C₁₂H₂₂O₁₁ + conc. H₂SO₄→ 6C + 6H₂O

Question 8

Give one equation each to show the following properties of sulphuric acid :

(i) Dehydrating property

(ii) Acidic nature

(iii) As a non-volatile acid

Solution 8

(i) Dehydrating property of sulphuric acid:

H₂SO₄ has a great affinity for water, and therefore, it acts as a dehydrating agent.

(ii) Acidic nature of sulphuric acid:

It acts as a strong dibasic acid.

It reacts with metals, metal oxides, metal hydroxides and carbonates to form metallic sulphates and hydrogen at ordinary temperature.

 Mg + H₂SO₄→ MgSO₄ + H₂↑ 

 CuO + H₂SO₄ → CuSO₄ + H₂O

 2NaOH + H₂SO₄→ Na₂SO₄ + 2H₂O

 ZnCO₃ + H₂SO₄→ ZnSO₄ + H₂O + CO₂↑ 

(iii) As a non-volatile acid: 

It has a high boiling point, so it is used to prepare volatile acids such as HCl, HNO₃ and acetic acid from their salts.

NaCl + H₂SO₄→ NaHSO₄ + HCl

NaNO₃ + H₂SO₄ → NaHSO₄ + HNO₃

CH₃COONa + H₂SO₄ → NaHSO₄ + CH₃COOH

Question 9

(i) Give balanced chemical equations for the action of sulphuric acid on each of the following

1. Potassium hydrogen carbonate

2. Sulphur

(ii) In the contact process for the manufacture of sulphuric acid give the equations for the conversion of sulphur trioxide to sulphuric acid.

Solution 9

(i)  

1. Action of sulphuric acid on potassium hydrogen carbonate

2KHCO₃ + H₂SO₄→ K₂SO₄ + 2H₂O + 2CO₂↑ 

2. Action of sulphuric acid on sulphur

S + 2H₂SO₄→ 3SO₂ + 2H₂O

(ii) In the contact process for the manufacture of sulphuric acid, the equations for the conversion of sulphur trioxide to sulphuric acid are

SO₃ + H₂SO₄→ H₂S₂O₇

(oleum or pyrosulphuric acid)

H₂S₂O₇ + H₂O → 2H₂SO₄

Chapter 10 - Study of Sulphur Compound: Sulphuric Acid Exercise 256

Question 1

A,B,C and D summarise the properties of sulphuric acid depending on whether it is dilute or concentrated.

A = Typical acid property

B = Non-Volatile acid

C = Oxidising agent

D = Dehydrating agent

Choose the property (A,B,C or D) depending on which is relevant to each of the following :

(i) Preparation of hydrogen chloride gas

(ii) Preparation of copper sulphate from copper oxide

(iii) Action of cone, sulphuric acid on sulphur

Solution 1

(i) B

(ii) A

(iii) C

Question 2

Write balanced chemical equations to show :

(i) The oxidizing action of conc.sulphuric acid on carbon

(ii) The behavior of H2SO4 as an acid when it reacts with magnesium

(iii) The dehydrating property of conc.sulphuric acid

Solution 2

(i) 

(ii) 

(iii)